Do any decision problems exist outside NP and NP-Hard?
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This question asks about NP-hard problems that are not NP-complete. I'm wondering if there exist any decision problems that are neither NP nor NP-hard. In order to be in NP, problems have to have a verifier that runs in polynomial time on a deterministic Turing machine. Obviously, all problems in P meet that criteria, but what about the problems with sub-exponential complexity? They do not belong to P and it's not obvious to me that they all have efficient deciders. And they certainly don't qualify...
Answer:
NP contains all (decision) problems that are at most as hard as NP-complete problems with respect to...
Sebastian Goodman at Computer Science Mark as irrelevant Undo
Other solutions
Answer:
Simply put, there are problems that are harder than all problems in NP, and if they could be solved...
Tim Wilson at Quora Mark as irrelevant Undo
The Millennium Problems are: Yang–Mills and Mass Gap Experiment and computer simulations suggest the existence of a "mass gap" in the solution to the quantum versions of the Yang-Mills equations. But no proof of this property...
Answer:
Not everything in mathematics must have a real-life application. In fact, most results in mathematics...
Barak Shoshany at Quora Mark as irrelevant Undo
All Problems in NP can be mapped to itself, implying that all NP problems are NP-hard problems. So, NP-hard should completely cover NP. I know I am surely wrong somewhere. I would like to know what is wrong with this argument.
Answer:
The proposition is: "NP- hard problems are at least as hard as the HARDEST problem in NP."...
Sumit Kushwaha at Quora Mark as irrelevant Undo
Imagine, hypothetically, if we were to build computers that could solve even the most complex NP-hard problems. This imaginary computer would be so fast that even the exponential slow-down of NP-hard problems doesn't become apparent (a kind of oracle...
Answer:
Cryptography breaking. After quantum computers become popular, passwords and security as we know it...
Dan Zhang at Quora Mark as irrelevant Undo
In the same sense that the Banach-Tarski Paradox doesn't provide an explicit construction, despite showing that that a sphere can be decomposed into a finite number of pieces and reassembled without stretching/funny business. I realize that this question...
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There is a possibility that even if P=NP we cannot prove it so. There's even the possibility that we...
Mark Gordon at Quora Mark as irrelevant Undo
I can't find the answer through googling, so here goes: I would think that attacking (finding a pre-image of) a hash digest would be NP complete in one sense: it's easy to very a hash inversion (putting it in NP), but difficult to find that pre-image...
Answer:
You have a few misunderstandings in your question. Hash inversion cannot be in NP or NP-hard because...
Tim Wilson at Quora Mark as irrelevant Undo
I know about P, NP, and NP-complete. As I see it, NP-complete is just a subset of NP, there are problems in NP cannot be reduced to other NP problems. Why does P=NP imply NP=NP-complete?
Answer:
Does this help? You must be signed in to read this answer.Continue with GoogleConnected to GoogleContinue...
Bret Fontecchio at Quora Mark as irrelevant Undo
As the question says, I am wondering if there are problems in NP which are not NP-complete (or not known to be NP-complete) but it is unknown if they are in P? More specifically, I am also wondering under what class did primality testing fall in before...
Answer:
Problems that are in NP, and are not NP-complete or in P are called NP-indeterminate (or NP-intermediate...
James Gay at Quora Mark as irrelevant Undo
can something be np- hard but np- complete?
Answer:
yes this one is mentioned in the examples section of the wiki for np hard it's an np complete problem...
pooya at Yahoo! Answers Mark as irrelevant Undo
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