How do you calculate lattice energy?
Let’s learn how do you calculate lattice energy. The most accurate or helpful solution is served by Yahoo! Answers.
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Use the Born-Haber cycle to calculate the lattice energy of CaO. You may need the following data: electron affinity of oxygen EA 1 = -141 kJ/mol, EA 2 = 744 kJ/mol; ionization energy of calcium IE 1 = 590 kJ/mol}, IE 2 = 1145 kJ/mol. Please help! I'm...
Answer:
You need to use a Born Haber diagram . In it you'll need to use both 1st and 2nd IE for Ca to get Ca...
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Other solutions
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for CaO http://www.gerry.spalton.btinternet.co.u… for NaCl which is similar to KCl -- https:...
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Answer:
The lattice energy of an ionic solid is a measure of the strength of bonds in that ionic compound. It...
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Answer:
The lattice energy (LE)of an ionic compound is the energy required to break apart the ions in their...
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Answer:
The Lattice Energy of CaO is: 193+590+1010+(498/2)-141+878+?H(lattice energy)= -635
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Calculate the lattice energy of AgCl using the following data: Ag(s) => Ag(g) ΔH = +284 kJ/mol Ag(g) => Ag+(g) + e- ΔH = +731 kJ/mol Cl2(g) => 2Cl(g) ΔH = +244 kJ/mol Cl(g) + e- => Cl-(g) ΔH = -349 kJ/mol Ag(s) + ...
Answer:
Hi reason no one answered your question is this is definitely easier to answer with a diagram and that...
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Calculate the energy change in kJ for the formation of 0.69 mol of LiCl(s) given the following information: Li(g) → Li(s) : −159.4 KJ/mol 2Cl(g) → Cl2(g) : −243.358 KJ/mol Li+(g) + e− → Li(g) : −520 KJ/mol Electron...
Answer:
This is an application of the Born-Haber cycle calculation. The Enthalpy of formation (per mole) = The...
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Calculate the energy change in kJ for the formation of 1.19 mol of KBr(s) given the following information: Br2(l) → Br2(g) : 30.92 KJ/mol K(g) → K(s) : −180.4 KJ/mol 1/2 Br2(g) →...
Answer:
To form KBr, the total reaction scheme is: 1/2 Br2(l) + K(g) → K(s) + Br(g) K(g) ...
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The lattice energy of KCl(s) is −715 KJ/mol, and the enthalpy of hydration is −684 KJ/mol. Calculate the enthalpy of solution (KJ) of 0.810 moles of KCl.
Answer:
It's -684 - (-715) = +31kJ/mol (so it's endothermic, NOT exothermic) So it's .81 * 31 = 25.11 kJ Huh...
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