# How do you find the derivative of a function?

Letâ€™s learn how do you find the derivative of a function. The most accurate or helpful solution is served by Yahoo! Answers.

There are ten answers to this question.

Best solution

Well there are specific formulae for specific functions but to work out any derivative you use f '(x...

Other solutions

The derivative of e^x is e^x. You need to find the derivative of the second part(i.e e^(-x^2)/4) and...

How does the derivative of a function help you find its range?

for example the function is (2x) ------ sq rt(x^2+x+1) and the derivative is (x+2) ------------------------ (9x^2+x+1)^(3/2) Using the derivative how do you find the range?

If you solve for df/dx = 0, you will get the x values for which the function has relative maxima and...

How do you find points of inflection of a derivative function?

f(x)=2x^3 -10x +3 you find the second derivative to determine if it is concave up or down, but I don't know how to find points of inflection. And how would you find the equation ...show more

In order to find Vertical Asymptotes you have to set the denominator equal to zero Now Horizontal Asymptotes...

Expand out the brackets and integrate.

How do i find the the derivative of the inverse of a function?

the function is y=x+(1/x) at y=17/4 once again, i need to find the derivative of the inverse of y. (the math section didn't answer)

Swap X and Y to get the inverse function: x = y + y^-1 Then use implicit differentiation: 1 = y' - y...

d/dx (6x^2 + 2x - 1)^7 = 7(6x^2 + 2x - 1)^6 * d/dx (6x^2 + 2x -1) = 7(6x^2 + 2x - 1)^6 * (12x + 2) ...

How do I find the derivative of this function step by step?

Hello everyone, I would like to find the derivative of the following step by step: -2/x(square root of x)

-2/[x(sqrt(x))] okay first lets combine the 2 x's on the bottom (x^1)(x^(1/2)) okay ya with me, add...

The derivative of ln u = u' / u. I like to call this derivative of stuff over stuff. To find the derivative...

y = cos^2 (x) + sin^2 (x) y = 1 dy/dx = 0 answer//

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