How do you find the derivative of a function?
Let’s learn how do you find the derivative of a function. The most accurate or helpful solution is served by Yahoo! Answers.
There are ten answers to this question.
Best solution
Answer:
Well there are specific formulae for specific functions but to work out any derivative you use f '(x...
Happy Boy at Yahoo! Answers Mark as irrelevant Undo
Other solutions
Answer:
The derivative of e^x is e^x. You need to find the derivative of the second part(i.e e^(-x^2)/4) and...
Paul at Yahoo! Answers Mark as irrelevant Undo
for example the function is (2x) ------ sq rt(x^2+x+1) and the derivative is (x+2) ------------------------ (9x^2+x+1)^(3/2) Using the derivative how do you find the range?
Answer:
If you solve for df/dx = 0, you will get the x values for which the function has relative maxima and...
Y!Addict at Yahoo! Answers Mark as irrelevant Undo
f(x)=2x^3 -10x +3 you find the second derivative to determine if it is concave up or down, but I don't know how to find points of inflection. And how would you find the equation ...show more
Answer:
In order to find Vertical Asymptotes you have to set the denominator equal to zero Now Horizontal Asymptotes...
KIGYCKBQSF6AKR6UN2F4FZPTSU at Yahoo! Answers Mark as irrelevant Undo
Math at Yahoo! Answers Mark as irrelevant Undo
the function is y=x+(1/x) at y=17/4 once again, i need to find the derivative of the inverse of y. (the math section didn't answer)
Answer:
Swap X and Y to get the inverse function: x = y + y^-1 Then use implicit differentiation: 1 = y' - y...
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Answer:
d/dx (6x^2 + 2x - 1)^7 = 7(6x^2 + 2x - 1)^6 * d/dx (6x^2 + 2x -1) = 7(6x^2 + 2x - 1)^6 * (12x + 2) ...
ss_lambo14 at Yahoo! Answers Mark as irrelevant Undo
Hello everyone, I would like to find the derivative of the following step by step: -2/x(square root of x)
Answer:
-2/[x(sqrt(x))] okay first lets combine the 2 x's on the bottom (x^1)(x^(1/2)) okay ya with me, add...
pietra at Yahoo! Answers Mark as irrelevant Undo
Answer:
The derivative of ln u = u' / u. I like to call this derivative of stuff over stuff. To find the derivative...
Christy K at Yahoo! Answers Mark as irrelevant Undo
Engr. Ronald at Yahoo! Answers Mark as irrelevant Undo
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