How to find the global equation of a dual curve?

Let’s learn how to find the global equation of a dual curve. The most accurate or helpful solution is served by Mathematics.

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How do I find the equation of a tangent line to a curve?

I'm given $x^2+2x-4$ at $x=2$ and I have to find the tangent line to this curve at that point...

Answer:

Here's an algebraic approach that avoids the explicit use of derivatives. We are given a quadratic function...

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How to find the equation and the set of values for the curve? PLEASE HELP, 10 POINTS?

A curve is such that dy/dx = 3 / (1+2x)^2 and the point (1, 1/2) lies on the curve. Find the equation of the curve. Then find the set of values of x for which the gradient of the curve is less than 1/3. Please help, 10 points?

Answer:

Where x = 1... dy/dx = 3/3² = 1/3 Now.. y - ½ = 1/3 * (x - 1) Good luck!

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How to find the equation and the set of values for the curve? PLEASE HELP, 10 POINTS?

A curve is such that dy/dx = 3 / (1+2x)^2 and the point (1, 1/2) lies on the curve. Find the equation of the curve. Then find the set of values of x for which the gradient of the curve is less than 1/3. Please help, 10 points?

Answer:

dy = 3 dx / (1+2x)^2 Let u = 1 + 2x, then (1/2) du = dx dy = (3/2) du / u^2 y = -(3/2) (1/u) + C y ...

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How to find the equation of the curve? PLEASE HELP, 10 POINTS?

A curve is such that dy/dx = 3 / (1+2x)^2 and the point (1, 1/2) lies on the curve. Find the equation of the curve, then find the set of values of x for which the gradient of the curve is less than 1/3. Please help me solve this problem, 10 points??

Answer:

When given such a question, where the dy/dx is given and a point on the curve is given, and asked to...

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How to find the equation of a tangent to the curve at P?

A curve has equation y=4/(3x-4) and P(2,2) is a point on the curve. Find the equation of the tangent to the curve at P. We got the solution which is: dy/dx = -4(3x-4)^-2 *3 if x=2, m=-3 Eqn of tangent: y-2=-3(x-2) Can someone explain to us how they did...

Answer:

triky

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How to find the equation of the curve? PLEASE HELP, 10 POINTS?

A curve has equation x^2 + 2y^2 + 5x + 6y = 10. Find the equation of the tangent to the curve at the point (2, -1). Give your answer in the form ax+by+c=0, where a, b, and c are integers. Please help me solve this problem, 10 points??

Answer:

x^2 + 2y^2 + 5x + 6y = 10 ----> implicit differentiation 2x + 4y * y' + 5 + 6y' = 0 4y * y' + 6y...

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I have a list of plot point(in excell) that result in an upward curve, how do I find the equation of the line.

I have a list of plot point(in excell) that result in an upward curve, how do I find the equation of the line. I need the equation to predict other point on that line however I cannot remember how to do so.

Answer:

If you have shown the trendline for your plot: -Right-click on trendline -Choose Format Trendline.....

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Answer:

Kind of hard to understand specifically what UR asking for? I'll make a couple of comments - maybe will...

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Answer:

First, you plot the points on a graph. Next, you draw a line of best fit, which is a line that is closest...

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How do I find the instantaneous velocity when I am only given the position curve but no equation?

I'm given a position curve, but no equation to take the derivative of, and the problem is asking for the instantaneous velocity at some point. Can anyone help? If you have Physics for Scientists and Engineers, 8th edition by Serway/Jewett; its problem...

Answer:

You have several possibilities. Not knowing the exact problem, here is the "Brute Force" solution...

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