Is this a basis for the Bergman space?
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By the way, what do you mean by "countable basis"? I assume that you are after an orthonormal basis for the Bergman space, but you should probably take note that ...
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Other solutions
I'm rather confused and I'm starting to think it's just the same thing described with different words. If I get the *dimension of the null space*, I'm looking for a number such as 2, right? If I get the *null space* of a matrix, I get the set of vectors...
Answer:
It seems that your confusion is coming from the term "basis." A basis (in this context) is...
Bob at Yahoo! Answers Mark as irrelevant Undo
related question: Why there is a neccesity to change the inner product definition (hence the distance definition) when I change the basis, in order to mantain the value of that distance the same? If I leave the inner product intact and change the basis...
Answer:
No, changing basis doesn't change the inner product or redefine length. A key idea here is that the...
Anonymous at Quora Mark as irrelevant Undo
I was wondering whether we can use row as well as column operations to reduce a matrix to find column space? Or do we only have to perform row operations to reduce matrix in case of row space and column operations to find column space?
Answer:
No, we cannot use row as well as column operations to reduce a matrix to find column space. Consider...
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Answer:
The easy way to do this is to think about what this subspace actually is, geometrically. It's a plane...
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When someone asks why time slows down significantly for a particle travelling near c, you often hear the following explanation: Spacetime is a continuum. The faster you travel through space, the slower you travel to time; that's a property of this continuum...
Answer:
When you are moving away from a position and then back to the position, very fast, your trajectory in...
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Answer:
In order for something to be a basis, it must be a linearly independent spanning set. Prove that it...
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Answer:
For any matrix A, I would do this by (1) Finding a basis (any basis) for the column space of A, then...
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