What is the empirical and molecular formula of the compound?
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Answer:
mass of C in 17.7 g of CO2 = 17.7 x MM C / MM CO3 = 17.7 x 12 / 44 = 4.827 g mass of H = 7.26 x 2 /...
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An organic compound contains C, H, N, and O. Combustion of 0.1023 g of the compound in excess oxygen yielded 0.2766 g of CO2 and 0.0991 g of H2O. A sample of 0.4831 g of of the compound was analyzed for nitrogen by the Dumas method. At STP, 27.6 mL of...
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Answer:
The compound you are looking for is C6H12O6, commonly known as glucose.With empirical formula CH2O and...
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Answer:
The empirical formula of a compound tells us the types of atoms present in a compound as well as the...
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Organic compound Z consists of elementary constituent compound of carbon, hydrogen and oxygen. When 0.75 g sample of the compound is burned completely, 1.10 g of CO2 and 0.45 g H2O are formed. The mass of 1.505 x 1023 molecules of Z is 15.02 g. 1) Calculate...
Answer:
mass of C in 1.10g of CO2 = 1.10 x 12 / 44 = .300 g of C mass of H in .45 g of H2O = .45 x 2 / 18 =...
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This will be a good website for you to review and learn this chemistry problems answer. http://rachel...
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The empirical formula of a compound is C4H9 and its molecular mass is 114.26 amu. Determine the compounds molecular formula.
Answer:
The molar mass of C4H9 is (12*2)+(1*9) = 57 114/57 = 2. Because the molar mass of the real molecule...
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Answer:
In chemistry, the empirical formula of a chemical compound is the simplest whole number ratio of atoms...
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Answer:
The compound you are looking for is C6H12O6, commonly known as glucose.With empirical formula CH2O and...
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Answer:
PHOSPHONATE ANALOGS OF HIV INHIBITOR COMPOUNDS This non-provisional application claims the benefit of...
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