# What is the pH at the equivalence point in the titration?

Letâ€™s learn what is the pH at the equivalence point in the titration. The most accurate or helpful solution is served by ChaCha.

There are ten answers to this question.

Best solution

Answer:

At the equivalence point, the pH = 7.00 for strong acid-strong base titrations.

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Anonymous at ChaCha

Other solutions

Answer:

0.010 L x 0.350 M = 0.00350 mole CH3COOH 0.00350 mole / 0.150 M = 0.0233 L NaOH At the equivalence point...

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DGAF. at Yahoo! Answers

What is the pH at the equivalence point from the titration of .145 g of a weak acid with .100 M NaOH?

The data table is shown as: Volume of NaOH added (mL)...................... pH 0.00....................................… 2.88 5.00 ........................................… 4.15 10.00...................................… 4.58 12....

Answer:

Hi pH = pKw / 2 + pKa / 2 + log( [salt] ) / 2

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mickeymo... at Yahoo! Answers

The pH at the equivalence point of an acid base titration was determined to be about 9.?

The pH at the equivalence point of an acid base titration was determined to be about 9. Describe the category of the titration in terms of the acid and base strength. ---Select--- a. strong acid/strong base b. weak acid/strong base c. weak acid/weak...

Answer:

B

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danxer at Yahoo! Answers

Answer:

pH = 5.56 at 36.0 ml(equivalence point)

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community wiki at wiki.answers.com

Calculate the pH at the equivalence point in the titration of 25.0 mL...?

Calculate the pH at the equivalence point in the titration of 25.0 mL of 0.250 molL-1 acetic acid (CH3COOH) with 0.0500 molL-1 NaOH. For CH3COOH, Ka = 1.80 x 10-5. Any help would be appreciated. Preferably a guide through it XD

Answer:

at equivalence pt mmole of acid =mmoles of base mmole= mL x M sooo mmoles pf acid = 25 mL x 0.25M =...

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Tatara at Yahoo! Answers

Calculate the pH at the equivalence point of the titration of 48 mL of 0.3 M NH3(aq) with 0.3 M HCl(aq). Ka(NH?

Calculate the pH at the equivalence point of the titration of 48 mL of 0.3 M NH3(aq) with 0.3 M HCl(aq). Ka(NH4+)=5.6 x 10-10

Answer:

See: http://answers.yahoo.com/question/index?…

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hcbioche... at Yahoo! Answers

Titration of 35.00 mL of 0.175 M caffeine using a .275 M HCl solution. Calculate pH and equivalence point.?

Calculate pH when 0, 5, 10.5, 17, 21, 26 and 31 mL of HCl are added. What is the equivalence point and it's pH?

Answer:

Haha I wish I knew the answer to this. Dr. O im guessing

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3QF523CPIGYXSASVJGXS3G4XGM at Yahoo! Answers

Calculating the pH at the Equivalence Point of a Titration?

Titration of 50.0 mL of 0.20M NH3 (Kb= 1.8 e(-5)) with 0.20M HNO3. Calculate pH after adding 50.0 mL of HNO3.

Answer:

Stephen, Look this answer: http://answers.yahoo.com/question/index;…

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Stephen at Yahoo! Answers

Answer:

a) the pH of a weak base and strong acid titration will be slightly acidic because you will produce...

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anon at Yahoo! Answers

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