What was the molar concentration of acetic acid in the vinegar?
Let’s learn what was the molar concentration of acetic acid in the vinegar. The most accurate or helpful solution is served by Yahoo! Answers.
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Answer:
The molecular weight of acetic acid is 60.05 grams/mol. So 12.4g/60.05g/mol = 0.206 moles. And there...
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I have volume of vinegar = 10mL But the vinegar was diluted with distilled water (+ 90mL) so the new volume is 100mL Concentration of sodium hydroxide is 0.123M 3.66mL of NaOH was required to turn 25mL of the diluted solution pink/ purplish Anyone know...
Answer:
Hi Adrien, Titration equation : CH3COOH + HO(-) = CH3COO(-) + H2O Concentration of the diluted vinegar...
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Answer:
Determination of acetic acid concentration in commercially available white vinegar is one of the simplest...
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Concentration of diluted vinegar = 0.1398mol/L Concentration of acetic acid in undiluted vinegar = 0.02796mol/L Molar Mass (CH3COOH) = 60.052 g/mol Express the concentration of acetic acid in the units of weight percent, i.e: grams of acetic acid per...
Answer:
0.1398mole/L 1L = 1000g. 0.1398mole x 60.052g/mole = 8.395g. 8.395g / 1000g x 100 = 0.8395% (It doesn...
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1. The concentration of acetic acid in vinegar was determined by titrating a known volume of the vinegar solution with a solution of 0.500 M NaOH. Identify the solution known as the analyte. 2. The concentration of acetic acid in vinegar was determined...
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5% wv acetic acid= 5 grams acetic acid 100mL vinegar a) The chemical formula for acetic acid is HC2H3O2. Determine the molar mass of acetic acid. b) Now convert the concentration of acetic acid in vinegar (5 grams acetic acid/100 mL vinegar) into Molarity...
Answer:
a) To determine the molar mass, simply add the atomic weights of every atom in the compound. H = 1....
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In the lab we used 3ml of vinegar solution, titrated with 12.15 ml NaOH. Concentration of NaOH used was 0.09846M . We have to calculate the following: 1. Moles of NaOH required to reach the equivalence point? 2. Moles of acetic acid 5.0 ml of vinegar...
Answer:
Based on the official monograph of acetic acid from USP each mL of 0.1M of NaOH is equivqlent to 6....
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Anonymous at ChaCha Mark as irrelevant Undo
If vinegar contains 5% acetic acid which translates into a 0.87mol/L concentration of acetic acid. The concentration of acetic acid in the vinegar sample should be the same. The sample of vinegar is diluted by 10 to make a 100.0mL solution and it is...
Answer:
To answer this question, you need to know the concentration of the NaOH. BTW, do you mean 13.0 mL of...
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The molarity of vinegar is 0.992M Calculate the mass of acetic acid (HC2H3O2) I calculated 60.06grams Calculate the grams of acetic acid per liter by multiplying the molarity by the molar mass. 0.992 x 60.06= 59.58 grams per liter. This is the part I...
Answer:
If there are 59.58 grams per liter, there are 59.58 grams per 1000 ml (because 1 liter = 1000 ml) and...
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