How to calculate pH of HCl in water?
Let’s learn how to calculate pH of HCl in water. The most accurate or helpful solution is served by Yahoo! Answers.
There are ten answers to this question.
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Answer:
First you must convert this HCl value into mols, then into mol/L. HCl molar mass: 36.46 g/mol. 0.18...
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Other solutions
Answer:
ok M=Molarity= mol/L mol=M*L=.002M*L=.002mol 2000mls=2L answer is M=.002mol/2L=.01M and pH=2
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What is my procedure in calculating the pH of a 0.1mol/l solution of NaCl? I found the pH of water, in an experiment to be 4.59. How do I use it in the a strong acid and strong base buffer, which I believe doesn't exist? i.e NaCl ---------------->...
Answer:
NaOH and HCl are strong electrolytes so you must use the auti ionization of water [H+] [OH-]= 1.0 x...
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What is the pH of a 0.240 molar HBr solution? Kw changes for a sample of water when there is a change in which of the following conditions? (Select all that apply.) 1 temperature [H+] [OH-] pressure What is the pH of a 0.058 molar Ba(OH)2 solution? What...
Answer:
1) pH = -log([H+]) = -log(0.24) = 0.620 2) Temp & pressure 3) pOH = -log(2 * 0.058) = 0.936. pH...
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Answer:
pH of water does matter in all cases, it all depends on the question being asked. Here, you can just...
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A solution is prepare by mixing 90.0 mL of 5.00 M HCL and 30.0 mL of 8.00 M HNO3. Water is then added until the final volume is 1.00 L. Calculate [H+], [OH-], and the pH for this solution.
Answer:
Calculate total H+ concentration 0.09L x 5 mol/L = 0.45 moles H+ from HCl 0.03L x 8 mol/L = 0.24 moles...
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Calculate the pH when 0.5mL of 0.1M HCl is added to 30mL pure water.
BASUP3JBSNDRN4GRIE2YYIVJMI at Yahoo! Answers Mark as irrelevant Undo
For each of the following three questions 25.0 mL of 0.100 M pyridine (Kb = 1.70 x 10−9) is titrated with 0.100 M HCl. For each question calculate the pH of the final solution after the indicated amount of HCl has been added. That is, treat each...
Answer:
pyridine (C5H5N) is a weak base and HCl is a strong acid... they react as : C5H5N + HCl ------->...
shadzlov... at Yahoo! Answers Mark as irrelevant Undo
Is this a trick question or am I missing something? 10^-6 moles of HCl gas is bubbled into a 10^6 L of pure water. What is the pH? It looks simple: 10^-6 mol / 10^6 L = 10^-12 M and then pH = -log(10^-12) = 12 But if you're adding an acid into pure water...
Answer:
There are two contributors to the H+ concentration. The added HCl contributes a concentration of 10...
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Answer:
If we assume V = 1 L: pH = -log[H+] = 5.5 [H+] = 10^-5.5 = 3.16 * 10^-6 M [HCl] = 2 M, so there are...
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